nariahtaylored37
Answered

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A six-sided number cube is rolled 900 times.

How many times is it expected that a number greater than 4 will be rolled?

Sagot :

nelsonclaire44

Answer: Rolling a die and obtaining a number follows a binomial distribution.

Expected value of binomial distribution is

E[X]=np

where n is number of toss and p is probability of obtaining the number.

Therefore here the expected value of obtaining a number 4 is:

E[X]=900∗16=150

Step-by-step explanation:

MrRoyal

It is expected that a number greater than 4 will be rolled 300 times

The sample space of a die is:

S = {1,2,3,4,5,6}

The probability of obtaining a number greater than 4 is:

[tex]p = 2/6[/tex]

[tex]p = 1/3[/tex]

In 900 rolls, the expected number of number greater than 4 is:

[tex]E(x) = p *n[/tex]

This gives

[tex]E(x) = 1/3 *900[/tex]

[tex]E(x) =300[/tex]

Hence, it is expected that a number greater than 4 will be rolled 300 times

Read more about expected values at:

https://brainly.com/question/15858152

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