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Sagot :
He lifted the box as high as 1.2 m (B).
Introduction
Hi ! In this question, I will help you. Work is the amount of force exerted to cause an object to move a certain distance from its starting point. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :
[tex] \boxed{\sf{\bold{W = F \times s}}} [/tex]
With the following condition :
- W = work (J)
- F = force (N)
- s = shift or displacement (m)
Now, because in this question, the "s" is a displacement that proportion to the change of altitude of the objects. So, the "s" can be written as "∆h* (altitude change). The formula can also be changed to:
[tex] \boxed{\sf{\bold{W = F \times \Delta h}}} [/tex]
With the following condition :
- W = work (J)
- F = force (N)
- [tex] \sf{\Delta h} [/tex] = change of altitude (m)
Problem Solving
We know that :
- W = work = 120 J
- F = force = 100 N
What was asked :
- [tex] \sf{\Delta h} [/tex] = change of altitude = ... m
Step by step :
[tex] \sf{W = F \times \Delta h} [/tex]
[tex] \sf{120 = 100 \times \Delta h} [/tex]
[tex] \sf{h = \frac{120}{100}} [/tex]
[tex] \boxed{\sf{h = 1.2 \: m}} [/tex]
Conclusion :
He lifted the box as high as 1.2 m (B).
See More :
- Work that he had done to lift object https://brainly.com/question/26341717
- Converting work to potential energy https://brainly.com/question/26487284
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