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Graph a line that contains the point (-5,-3) (−5,−3) with a slope of -2

What's the answer please help??

Sagot :

rspill6

Answer:

See below and attached graph.

Step-by-step explanation:

The slope-intercept form of a straight line equation is y = mx + b, where m is the slope and b the y-intercept (the value of y when x = 0).

With a slope of -2, we can write:

y = -2x + b

To find b, enter the given point (-5,-3) and solve for b:

y = -2x + b

-3 = -2(-5) + b

-3 = 10 + b

b = -13

The equation becomes:  y = -2x -13

See the attached graph.

View image rspill6
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