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8x/10x-2 equals 5x+3/7x solve for x

Sagot :

somesortapapaya

Answer:

x = [tex]\frac{1}{3}[/tex] & 3

Step-by-step explanation:

[tex]\frac{8x}{10x-2}[/tex] = [tex]\frac{5x+3}{7x}[/tex]

Cross multiply:

[tex]\frac{8x}{10x-2}[/tex] = [tex]\frac{5x+3}{7x}[/tex]   ⇒   (8x)(7x) = (5x+3)(10x-2)

Simplify both sides:

(8x)(7x) = (5x+3)(10x-2)   ⇒   56x² = 50x²+20x-6

Set equation equal to 0:

56x² = 50x²+20x-6   ⇒   0 = -6x²+20x-6

Factor the trinomial:

0 = -6x²+20x-6 = (-6x+2)(x-3)

Solve for X:

-6x+2 = 0

-6x = -2

x = [tex]\frac{1}{3}[/tex];

x-3 = 0

x = 3;

x = [tex]\frac{1}{3}[/tex], 3

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