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How many moles of hydrogen are in 3. 06 × 10⁻³ g of glycine , c₂h₅no₂?.

Sagot :

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Answer:

n = 6.06 x [tex]10^{-4}[/tex] mol

Explanation:

n =?

m = 3.06 x 10-³ g

M (H5) = 5 x 1.01 (Since we only want hydrogen)

Atomic mass of C = 12.01

Atomic mass of H is 1,01, etc.

Having this data, we can use the Molar mass formula and change it so we can know the quantity of matter (n) in moles, and we just replace it.

M = [tex]\frac{m}{n}[/tex] ⇔ n = [tex]\frac{m}{M}[/tex] ⇔ n = [tex]\frac{3.06 x 10^{-3} }{5,05}[/tex] ⇔ n = 6.06 x [tex]10^{-4}[/tex] mol

Note: The numbers I've used may be different from yours, by a small difference. I don't know if it's the case, but hope it helped.

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