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A compound is found to contain 36.5% Na, 25.4% S, and 38.1% O. Find its empirical formula.

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ajinems

The empirical formula of the compound is =NaSO2

Empirical formula

This is the formula that analyses the different ratios of atoms in a compound in its simplest form.

To calculate the empirical formula use the least atom percentage ratio. That is,

[tex]na = \frac{36.5}{25.4} = 1.437[/tex]

[tex]s = \frac{25.4}{25.4} = 1[/tex]

[tex]o = \frac{38.1}{25.4} = 2[/tex]

From the calculation, the ratio of the various atoms are

NaSO2

Therefore the empirical formula is NaSO2

Learn more about empirical formula here:

https://brainly.com/question/1603500

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