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I need to know the solution and the formula.

I Need To Know The Solution And The Formula class=

Sagot :

Statement:

A non-deformed spring is 15 cm long. When a 2.0 N force is applied to it, its length becomes 19 cm.

To find out:

The spring constant of the spring.

Solution:

  • Force (F) = 2 N

  • Extension of the spring (x)
  • = (19 - 15) cm
  • = 4 cm
  • = 0.04 m [since we have to find the answer in N/m]

  • Let the spring constant of the spring be k.

  • We know, the formula of spring force, i.e.,
  • F = kx

  • Putting the values in the above formula, we get
  • 2 N = k × 0.04 m
  • or, k = 2 N ÷ 0.04 m
  • or, k = 50 N/m

Answer:

The spring constant of this spring is 50 N/m.

Hope you could understand.

If you have any query, feel free to ask.

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