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Sagot :
- Length of wire be l=1
Electric field intensity
[tex]\\ \tt\hookrightarrow \dfrac{V}{l}[/tex]
[tex]\\ \tt\hookrightarrow \dfrac{100}{l}[/tex]
[tex]\\ \tt\hookrightarrow 100N/C[/tex]
The electric field intensity across the wire depends upon the voltage and its length. The electric field intensity across the wire is 100 V/m.
What is the electric field intensity?
The electric field intensity is defined as the force experienced by the unit positive charge placed at that point.
Given that the voltage is 100 V. If the length of the wire is 1m, then the electric field intensity across the wire is given as below.
[tex]E = \dfrac {V}{d}[/tex]
Where E is the electric field intensity, V is the voltage across the wire and d is the length of the wire.
[tex]E = \dfrac {100}{1}[/tex]
[tex]E = 100 \;\rm V/m[/tex]
Hence we can conclude that the electric field intensity across the wire is 100 V/m.
To know more about the electric field intensity, follow the link given below.
https://brainly.com/question/3104386.
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