johnmikelgarcia
Answered

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Where is the hole for the following function located?
X+3
(
f(x)=(x-4)(x+3)
Ox=-3
O y=-3
O x= 3
O y=3

Sagot :

uwukianna
The hole of a function is described as the x-y coordinate wherein the denominator and numerator equates to zero. For the function f(x)= x+3/(x+4)(x+3), the common polynomial given is x-3 which can be equated to zero. Hence, 0 divided 0 means a hole in the function. If x+3 = 0, the hole of the function is at x = -3. ^w^
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