Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
[tex]=\int\limit(\frac{1}{t^{2} }-\frac{2}{t^{3} }) dt \\\\=\int\limit\frac{1}{t^{2} }dt-2\int\limit\frac{1}{t^{3} }dt\\\\=-\frac{1}{t}-2 \int\limit\frac{1}{t^{3} }dt\\\\=\frac{1-t}{t^{2} }[/tex]
Step-by-step explanation:
[tex]\\ \tt\hookrightarrow {\displaystyle{\int}}\left(\dfrac{1}{t^2}-\dfrac{2}{t^3}\right)dt[/tex]
[tex]\\ \tt\hookrightarrow {\displaystyle{\int}}(t^{-2}-2t^{-3})dt[/tex]
[tex]\\ \tt\hookrightarrow {\displaystyle{\int}}t^{-2}-2{\displaystyle{\int}}t^{-3}dt[/tex]
[tex]\\ \tt\hookrightarrow \dfrac{t^{-1}}{-1}-2\dfrac{t^{-2}}{-2}[/tex]
[tex]\\ \tt\hookrightarrow \dfrac{-1}{t}+\dfrac{1}{t^2}[/tex]
[tex]\\ \tt\hookrightarrow \dfrac{-2+1}{t^2}[/tex]
[tex]\\ \tt\hookrightarrow \dfrac{-1}{t^2}[/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.