hope5849
Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

help me plz......... ​

Help Me Plz class=

Sagot :

Nepalieducation

[tex]=\int\limit(\frac{1}{t^{2} }-\frac{2}{t^{3} }) dt \\\\=\int\limit\frac{1}{t^{2} }dt-2\int\limit\frac{1}{t^{3} }dt\\\\=-\frac{1}{t}-2 \int\limit\frac{1}{t^{3} }dt\\\\=\frac{1-t}{t^{2} }[/tex]

Step-by-step explanation:

[tex]\\ \tt\hookrightarrow {\displaystyle{\int}}\left(\dfrac{1}{t^2}-\dfrac{2}{t^3}\right)dt[/tex]

[tex]\\ \tt\hookrightarrow {\displaystyle{\int}}(t^{-2}-2t^{-3})dt[/tex]

[tex]\\ \tt\hookrightarrow {\displaystyle{\int}}t^{-2}-2{\displaystyle{\int}}t^{-3}dt[/tex]

[tex]\\ \tt\hookrightarrow \dfrac{t^{-1}}{-1}-2\dfrac{t^{-2}}{-2}[/tex]

[tex]\\ \tt\hookrightarrow \dfrac{-1}{t}+\dfrac{1}{t^2}[/tex]

[tex]\\ \tt\hookrightarrow \dfrac{-2+1}{t^2}[/tex]

[tex]\\ \tt\hookrightarrow \dfrac{-1}{t^2}[/tex]

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.