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Write x²-10x+32 in vertex form


Sagot :

Answer:

y = (x-5)²+7

Step-by-step explanation:

i graphed x²-10x+32 and found the vertex is at (5,7)

i used the y-intercept as a point on the curve in the formula:

y = a(x-h)²+k

32 = a(0-5)²+7

subtract 7 from each side to get:

25 = 5²a

25 = 25a

a = 1

y = (h-5)² + 7

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