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Sagot :
We need volume
[tex]\\ \tt\hookrightarrow LBH[/tex]
- L=length
- B=width
- H=height
[tex]\\ \tt\hookrightarrow V=28(14)(5)[/tex]
[tex]\\ \tt\hookrightarrow V=1960ft^3[/tex]
- Rate of output=140ft
Total time
[tex]\\ \tt\hookrightarrow \dfrac{1960}{140}=14h[/tex]
Answer:
- 14 hours
Step-by-step explanation:
We know that:
- L = 28 ft.
- W = 14 ft.
- D = 5 ft.
- 140 ft. = 1h
Solution:
- Volume of pool: 28 x 14 x 5
- => Volume of pool: 14 x 14 x 5 x 2
- => Volume of pool: 196 x 10
- => Volume of pool: 1960 ft³
- => Time to empty the pool: 1960/140
- => Time to empty the pool: 14 hours
Hence, it takes 14 hours to empty the pool.
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