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Two men pull on a 31-kg box with forces 8.3 N and 6.6 N in opposite directions.
Find the resultant acceleration of the box and the direction in which the box moves.

Sagot :

onyebuchinnaji

The resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.

The given parameters:

  • Mass of the box, m = 31 kg
  • Two applied forces, = 8.3 N and 6.6 N

Resultant force on the box

The resultant force on the box is calculated as follows;

[tex]F_{net} = F_1 - F_2\\\\F_{net} = 8.3 \ N - \ 6.6 \ N\\\\F_{net} = 1.7 \ N[/tex]

Resultant acceleration of the box

The resultant acceleration of the box is calculated as follows;

[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{1.7}{31} \\\\a = 0.055 \ m/s^2[/tex]

Thus, the resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.

Learn more about resultant acceleration here: https://brainly.com/question/26216029

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