The resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.
The given parameters:
- Mass of the box, m = 31 kg
- Two applied forces, = 8.3 N and 6.6 N
Resultant force on the box
The resultant force on the box is calculated as follows;
[tex]F_{net} = F_1 - F_2\\\\F_{net} = 8.3 \ N - \ 6.6 \ N\\\\F_{net} = 1.7 \ N[/tex]
Resultant acceleration of the box
The resultant acceleration of the box is calculated as follows;
[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{1.7}{31} \\\\a = 0.055 \ m/s^2[/tex]
Thus, the resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.
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