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Sagot :
Answer:
The equation has no solution
Step-by-step explanation:
[tex]{ \tt{a + 5(2a - 1) + 3 = 11a - 2}} \\ { \tt{a + 10a - 5 + 3 = 11a - 2}} \\ { \tt{11a - 2 = 11a - 2}} \\ { \tt{11a - 11a = - 2 + 2}} \\ { \red{ \tt{0 = 0}}}[/tex]
Answer:
D, or Infinite Solutions
Step-by-step explanation:
We have the equation a + 5(2a - 1) + 3 = 11a - 2
Solve the equation and see if there's a solution or not.
a + 5(2a) - 5(1) + 3 = 11a - 2
a + 10a - 5 + 3 = 11a - 2
11a - 2 = 11a - 2
Since both equations are the same, then any value of a will satisfy the equation, making it have infinite solutions. Hope this helps.
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