At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

I have been struggling with this for a while lol​

I Have Been Struggling With This For A While Lol class=

Sagot :

Answer:

  f(x) = (3x -2)(2x +1)

Step-by-step explanation:

The procedure for factoring expression of the form ...

  ax² +bx +c

is to look for factors of a·c that have a sum of b.

The product a·c is 6·(-2) = -12. You are looking for factors that have a sum of b = -1. From your familiarity with multiplication tables, you know ...

  -12 = 1(-12) = 2(-6) = 3(-4)

The sums of the factor pairs in this list are -11, -4, -1. So, the last pair of factors, {3, -4} is the one we're looking for.

__

At this point, there are several ways to proceed. Perhaps the simplest is to rewrite the linear term as the sum of terms involving these factors:

  -x = 3x -4x

  f(x) = 6x² +3x -4x -2

Now, the expression can be factored 2 terms at a time:

  f(x) = (6x² +3x) -(4x +2) . . . . . pay attention to signs

  f(x) = 3x(2x +1) -2(2x +1) . . . . factor each pair

  f(x) = (3x -2)(2x +1) . . . . . . . . factor out the common factor of (2x+1)