Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Sinx = opps/hyp = 1/2
2^2 = 1^2 + x^2
x = sqrt(3) = adj
Cosx = adj/hyp = sqrt(3)/2
2^2 = 1^2 + x^2
x = sqrt(3) = adj
Cosx = adj/hyp = sqrt(3)/2
Value of cos x = ( √3 / 2) for 0° < x° < 90°.
What are trigonometric function?
" Trigonometric function is defined as the relation between sides and angles of a right angled triangle."
Formula used
(Hypotenuse)² = ( Opposite side)² + ( Adjacent side)²
sinθ = (Opposite side) / (Hypotenuse)
cosθ = (Adjacent side) / (Hypotenuse)
According to the question,
Given,
0° < x° < 90°
sin x = 1 / 2
Substitute the value in the formula we get,
Opposite side = 1
Hypotenuse = 2
(2)² = (1 )² + (Adjacent side)²
⇒(Adjacent side)² = 4 - 1
⇒ Adjacent side = ±√3
0° < x° < 90°
cos x >0
Therefore,
cos x = √3 / 2
Hence, value of cos x = ( √3 / 2) for 0° < x° < 90°.
Learn more about trigonometric function here
https://brainly.com/question/6904750
#SPJ2
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.