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What is the molarity of a solution when 2. 75 g of nacl is dissolved in 1100 ml of solution.

Sagot :

ormula is:
Molarity
=
Moles of Solute
Liters of Solution
So, the first thing I would do is convert the 750 mL to Liters. This would equal: .750 L (KHDBDCM: M->B).
Next, calculate the moles of NaCl by using the formula:
Moles
=
Amount Available
Molar Mass

So, the number of moles would be
85.0
g
of NaCl
58.44g
(
Molar Mass
)
which would equal: 1.45448323066 mol.
Next, plug the numbers into the molarity formula which would be:
1.45448323066
mol
.750
L
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