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A student is standing 8 m from a roaring truck engine that is measured at 20. The student moves 4 m closer to the engine. What is the measured sound intensity at the new distance?.

Sagot :

facundo3141592

By knowing how intensity relates to distance, we will see that at 4 meters of the engine the intensity is 80.

How sound intensity relates to distance?

The sound spreads in a solid angle like all waves, so the intensity of the sound will decrease with the distance squared, this means that:

[tex]I = \frac{P}{4*pi*r^2}[/tex]

Where P is the sound power, we know that when the student is at 8m from the engine, the intensity measured is 20 (it does not tell the units) so we have:

[tex]20 = \frac{P}{4*3.14*(8m)^2} \\\\P = 20*4*3.14*(8m)^2 = 16,078.8 m^2[/tex]

Now, if you move 4 meters closer to the engine, your new position will be:

r = 4m

Then we have:

[tex]I = \frac{16,078.8 m^2}{4*3.14*(4m)^2} = 80[/tex]

If you want to learn more about sound intensity, you can read:

https://brainly.com/question/26376755

Joshuahudkins

Answer:

80 is the answer! 100% CORRECT!

Explanation:

~Hope this helps! :)

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