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Sagot :
The rule that represents the height of the ball after each bounce is;
H(n) = 400(0.8)^(n - 1)
Geometric Sequence Progression
From online sources, we have that;
After first bounce, height = 400 m
After 2nd bounce, height = 320 m
After 3rd bounce, height = 256 m
Formula for the nth term of a geometric sequence is;
T_n = ar^(n - 1)
First term is 400m
Since second term is 320, then common ratio is;
r = 320/400
r = 0.8
Thus, the 6th bounce which is the 6th term will be;
T_6 = 400 * 0.8^(6 - 1)
T_6 = 131 m
Read more about geometric sequence at; https://brainly.com/question/21688964
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