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Sagot :
Fractions are quotients of two integers
Dianne spends more time studying
How to determine who spent more time
Using the figures in the table, we start by calculating the time spent by each of them.
So, we have:
[tex]Mark = 2\frac 16 + 1\frac 56 + 3\frac 34 + 2\frac 18 + \frac 56[/tex]
Adding the fractions, we have:
[tex]Mark = 10 \frac{17}{24}[/tex]
Also, we have:
[tex]Dianne =2\frac 12 + \frac 56 + 3 \frac 23 + 3\frac 23 + \frac 34[/tex]
[tex]Dianne =11\frac 5{12}[/tex]
By comparison:
[tex]11\frac 5{12}[/tex] is greater than [tex]10\frac{17}{24}[/tex];
Hence, Dianne spends more time studying
Read more about fractions at:
https://brainly.com/question/11562149
Answer:
Diane spent more time studying
Step-by-step explanation:
In general, the question can be answered a couple of ways:
- by summing the daily differences in time
- by summing the times for the week and comparing the results
Here, the fractions with different denominators tend to make it easier to use the latter approach.
Either way, the fractions are summed by expressing them using a common denominator. The denominators of 2, 3, 4, 6, and 8 are all factors of 24, so it is convenient to express all of the fractions using 24 as a denominator.
__
Mark's total time for the week is ...
(2 1/6) +(1 5/6) +(3 3/4) +(2 1/8) +(5/6)
= (2 +1 +3 +2 +0) +(1/6 +5/6 +3/4 +1/8 +5/6)
= 8 +(4/24 +20/24 +18/24 +3/24 +20/24)
= 8 +(4 +20 +18 +3 +20)/24 = 8 +65/24 = 8 +2 17/24
= 10 17/24 . . . hours
__
Diane's total time for the week is ...
(2 1/2) +(5/6) +(3 2/3) +(3 2/3) +(3/4)
= (2 +0 +3 +3 +0) +(1/2 +5/6 +2/3 +2/3 +3/4)
= 8 + (12/24 +20/24 +16/24 +16/24 +18/24)
= 8 +(12 +20 +16 +16 +18)/24 = 8 +82/24 = 8 +3 10/24
= 11 5/12 . . . hours
At 11 5/12 hours for the week, Diane's total is greater than Mark's total of 10 17/24 hours for the week.
Diane spent more time studying by the end of the week.
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