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Sagot :
Answer:
[tex]f^{-1}(x) = ( \frac{4y - 36}{-3} )[/tex]
Step-by-step explanation:
f(x)=-3/4x+9
let f(x) be y .......................to find inverse we have making x the subject.
y = -3/4x+9
y - 9 = -3/4 x
-3x = 4y - 36
x = (4y - 36)/-3
so, [tex]f^{-1}(x) = ( \frac{4y - 36}{-3} )[/tex]
- Let y=f(x)
[tex]\\ \tt\hookrightarrow y=\dfrac{-3}{4}x+9[/tex]
[tex]\\ \tt\hookrightarrow y-9=\dfrac{-3x}{4}[/tex]
[tex]\\ \tt\hookrightarrow -3x=4y-36[/tex]
[tex]\\ \tt\hookrightarrow x=\dfrac{-4}{3}y+12[/tex]
Now
[tex]\\ \tt\hookrightarrow f^{-1}x=\dfrac{-4}{3}x+12[/tex]
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