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consider the following function: f(x)=-3/4x+9
place the steps for finding f-1 (x) in the correct order


Sagot :

Answer:

[tex]f^{-1}(x) = ( \frac{4y - 36}{-3} )[/tex]

Step-by-step explanation:

f(x)=-3/4x+9

let f(x) be y .......................to find inverse we have making x the subject.

y = -3/4x+9

y - 9 = -3/4 x

-3x = 4y - 36

x = (4y - 36)/-3

so, [tex]f^{-1}(x) = ( \frac{4y - 36}{-3} )[/tex]

  • Let y=f(x)

[tex]\\ \tt\hookrightarrow y=\dfrac{-3}{4}x+9[/tex]

[tex]\\ \tt\hookrightarrow y-9=\dfrac{-3x}{4}[/tex]

[tex]\\ \tt\hookrightarrow -3x=4y-36[/tex]

[tex]\\ \tt\hookrightarrow x=\dfrac{-4}{3}y+12[/tex]

Now

[tex]\\ \tt\hookrightarrow f^{-1}x=\dfrac{-4}{3}x+12[/tex]