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-8-8x^2=-31
how to solve for x

Sagot :

Intriguing456

Answer:

x = ± [tex]\sqrt{\frac{23}{2\sqrt{2}}}[/tex]

Step-by-step explanation:

-8 - 8x^2= -31

Since this is a quadratic, it needs to be factored.

First, move the x to the other side:

-8 = 8x^2 - 31

Then, get the x alone by first adding 31:

23 = 8x^2

then dividing by 8:

x^2 = 23/8

Finally, square root both sides and remember the even roots property:

x = ± [tex]\sqrt{\frac{23}{8}}[/tex]

and simplify the root 8:

x = ±  [tex]\sqrt{\frac{23}{2\sqrt{2}}}[/tex]

Note: This answer may have a mistake.

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