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Can someone help with this, i’m getting lost in the steps. Like I start off right (i think) then it just gets confusing.

Can Someone Help With This Im Getting Lost In The Steps Like I Start Off Right I Think Then It Just Gets Confusing class=

Sagot :

Answer:

28.12 kg

Explanation:

Here we are given that the density of copper is 8.92 g/ cm³ .

[tex]\sf \longrightarrow \rho_{(copper)}= 8.92 g/cm^3\\ [/tex]

And we are interested in finding out the mass of the given block . The dimensions of the block is 0.052m × 311mm × 19.5 cm .

  • Firstly find out the volume in cm³ as the density is in cm³ .

[tex]\sf \longrightarrow Volume_{cuboid}= length * breadth * height \\ [/tex]

  • 1cm = 0.01 m
  • 1cm = 10mm

[tex]\sf \longrightarrow Volume = (0.052)(100) * (311\div 10) *(19.5) cm^3 \\ [/tex]

[tex]\sf \longrightarrow Volume = 5.2 * 31.1 * 19.5 cm^3 \\ [/tex]

[tex]\sf \longrightarrow Volume = 3153.54 cm^3\\ [/tex]

Now we may use Unitary Method to find out the mass of the block as ,

Mass of 1cm³ of copper is 8.92 g .

Mass of 3153.54 cm³ of copper will be 8.92*3153.54 g = 28129.57 g

  • And we know that 1kg = 1000g , so

[tex]\sf \longrightarrow \underline{\boxed{\bf Mass_{Cu}= 28.12 \ kg }} \\ [/tex]