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Sagot :
Answer:1,0.95cm
2,21.82cms
3, 2.73
Explanation:
1,Its equation is following: 1o + 1i = 1f
1i = 1f - 1o
1i = 1−11 - 125
i = -7.64 cm - the image distance from the lens. The negative sign means that the image virtuali
h = 3.1* 7.6425 = 0.95 cm - the diameter of the coin’s imageimage
2,Use the lens equation to determine the image distance: 1/25 = 1/80 + 1/Di →
Di = 36.36 cm.
The image is real and on the opposite side of the lens as compared to the object.
The distance between object and image then is: 80 + 36.36 = 116.36 cm.
3,1/V+1/U =1/F ; 1/V =1/F-1/U ;- 1/15–1/48 =16-5/ 240 = 11/240 ; V =240/11
=21.82 CMS
IMAGE MAGNIFICATION V /U =21.82/48= 0.0.4546INVERTED
6 * 0.4546=2.7276 ≈2.73
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