Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

A 50. 0 kg child is riding in a 120. 0 kg bumper car at an amusement park. The child drives the bumper car at 4. 5 m/s head-on into the wall of the ride and rebounds at the speed. What is the magnitude of the change in momentum of the child and the bumper car?.

Sagot :

Explanation:
Total mass of child and car = 50 + 120 = 170 kg .
initial velocity u = 4.5 m/s
initial momentum = mass x velocity = 170 x 4.5 = 765 kg m/s
final velocity = - 4.5 m/s [ - ve is due to reversal of direction ]
final momentum = - 765 kg m/s
change in momentum = final momentum - initial momentum
= - 765 - ( 765 )
= - 1530 kg m/s .
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.