MagnusCarlsen
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1) Solve ;

[tex]3(x - 5) \leqslant x - 8[/tex]

Notes :-

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Sagot :

semsee45

Answer:

x ≤ 7/2

Step-by-step explanation:

Expand brackets:                   3x - 15 ≤ x - 8

Subtract x from both sides:   2x - 15 ≤ -8

Add 15 to both sides:                    2x ≤ 7

Divide both sides by 2:                   x ≤ 7/2

OoBrainlyDemonoO28

Answer:

Hello There!

[tex] \huge \dag \sf \green{question}[/tex]

[tex]3(x - 5) \leqslant x - 8[/tex]

[tex] \rule{200pt}{5pt}[/tex]

[tex] \huge \hookrightarrow \sf \blue{answer}[/tex]

[tex] \rule{200pt}{5pt}[/tex]

Use the distributive property to multiply 3 by x-5

[tex]3x - 15 \leqslant x - 8 [/tex]

Subtract x from both sides

[tex]3x - 15 - x \leqslant 8[/tex]

Combine 2x and -x to get 2x

[tex]2x - 15 \leqslant - 8[/tex]

Add 15 to both sides

[tex]2x \leqslant - 8 + 15[/tex]

Add -8 and 15 to get 7

[tex]2x \leqslant 7[/tex]

Now divide both the sides by 2

As 2 is > 0, the inequality direction remains the same.

[tex]x \leqslant \frac{7}{2} \\ [/tex]

[tex] \rule{200pt}{5pt}[/tex]

Hope it helps you from my side

:)

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