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What is the equation of a line that is perpendicular to the line y = -3x + 2 and passes through the point (6,8)?

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Answer:

y = 1/3x+6

Step-by-step explanation:

y = -3x+2 is in slope intercept form  y = mx+b  where m is the slope and b is the y intercept

The slope is -3

Perpendicular lines have slopes that are negative reciprocals

The slope of the perpendicular line is  -1/-3 = 1/3

The equation of the new line is

y = 1/3x +b

Using the point that passes through the line ( 6,8) and substituting in for x and y

8 = 1/3(6) +b

8 = 2+b

8-2 =b

6 =b

The equation becomes

y = 1/3x+6

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