Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A line passes through the points (1.4) and (2, 2). What is the equation of this line?


Sagot :

Answer:

y = - 2x + 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ )  = (1, 4 ) and (x₂, y₂ ) = (2, 2 )

m = [tex]\frac{2-4}{2-1}[/tex] = [tex]\frac{-2}{1}[/tex] = - 2 , then

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, 2 ) , then

2 = - 4 + c ⇒ c = 2 + 4 = 6

y = - 2x + 6 ← equation of line

.5 is the slope and y=my+b is ur line equation