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Sagot :
Answer:
Molar mass of KClO₃ = (39 + 35.5 + 16×3) g/mol = 122.5 g/mol
Molar mass of KCl = (39 + 35.5) g/mol = 74.5 g/mol
Balanced equation for the reaction:
2KClO₃ → 2KCl + 3O₂
Mole ratio KClO₃ : KCl = 2 : 2
Moles of KClO₃ reacted = (2.73 g) / (122.5 g/mol) = 0.0223 mol
Moles of KCl formed = (0.0223 mol) × (2/2) = 0.02229 mol
Mass of KCl formed = (0.0223 mol) × (74.5 g) = 1.66 g
====
OR:
(2.73 g KClO₃) × (1 mol KClO₃ / 122.5 g KClO₃) × (2 mol KCl produced / 2 mol KClO₃) × (74.5 g KCl / 1 mol KCl)
= 1.66 g KCl produced
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