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It appears that the derivatives of sine and cosine are related. What about the second derivatives?.

Sagot :

Answer:

Step-by-step explanation:

[tex]\frac{d}{dx} (sin~x)=cos~x\\\frac{d}{dx}(cos~x) =-sin~x\\\frac{d^2}{dx^2} (sin~x)=\frac{d}{dx} (cos~x)=- sin~x\\\frac{d^2}{dx^2} (cos~x)=\frac{d}{dx} (-sin~x)=-cos~x[/tex]

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