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Sagot :
The given sequence the recursive function will be [tex]a_n = 4a_{n-1}[/tex]
The iterative rule for the sequence is [tex]T_n = 8(4)^{n-1[/tex]
Sequence and series
Given the sequence of numbers 8, 32, 128, 512, …
- a1 = 8
- a2 = 32 = 4(8)
- a3 = 128 = 4(32)
From the given sequence the recursive function will be [tex]a_n = 4a_{n-1}[/tex]
For the iterative sequence, we will use the common ratio and the first term as shown;
[tex]T_n=ar^{n-1}\\T_n=8(4)^{n-1}[/tex]
Hence the iterative rule for the sequence is [tex]T_n = 8(4)^{n-1[/tex]
Learn more on sequence here: https://brainly.com/question/7882626
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