Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
The total area of the walls is 140 m²
Since the room is in the shape of a cuboid, and we require the area of the walls of the room, the walls of the cuboid are the walls of the room.
Area of the room
So, the total surface area of a cuboid is A = 2(lb + lh + bh) where
- l = length of room,
- b = breadth of room and
- h = height of room.
Since we require the total area of the walls, lb which is the area of the floor is removed from the equation.
Area of the walls
So, the area of the walls is A' = 2(lh + bh)
= 2h(l + b)
Since the dimensions of the floor are 4 meters by 6 meters and the height of the basement is 7 m. So,
- l = 4 m,
- b = 6 m and
- h = 7 m
So, substituting the values of the variables into the equation, we have
A' = 2h(l + b)
A' = 2 × 7 m × (4 m + 6 m)
A' = 14 m × 10 m
A' = 140 m²
So, the total area of the walls is 140 m²
Learn more about total surface area of room here:
https://brainly.com/question/17048283
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.