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Sagot :
A regular hexagon has 6 congruent sides.
The dimension of the rectangle is 8 inches by [tex]4\sqrt 3[/tex] inches
How to determine the length of the rectangle
Start by calculating the value of x using the following cosine ratio
[tex]\cos(60) = \frac{x}{4}[/tex]
Make x the subject
[tex]x = 4 * \cos(60)[/tex]
Evaluate cos(60)
[tex]x = 4 * 0.5[/tex]
[tex]x = 2[/tex]
So, the dimension of the rectangle is:
[tex]Length = 2x + 4[/tex]
[tex]Width = 2x\sqrt 3[/tex]
This gives
[tex]Length = 2 * 2 + 4[/tex]
[tex]Length = 8[/tex]
[tex]Width = 2 * 2\sqrt 3[/tex]
[tex]Width = 4\sqrt 3[/tex]
Hence, the dimension of the rectangle is 8 by [tex]4\sqrt 3[/tex]
Read more about hexagons at:
https://brainly.com/question/2264170
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