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The mass in a pendulum clock completes one full back-and-forth oscillation in 1.25s.
What is the length of the rod (assuming its mass is negligible)?

Sagot :

thishigopal

Answer:

.38m

Explanation:

1.25 = 2π√l/g

removing square roots

1.5625 = 4*π^2*l/9.8

length = .38m

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