Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

PLEASE USE KINEMATIC EQUATION!!

A basketball is dropped from a height of 2.00 meters above the ground. On the first bounce the
ball reaches a maximum height of 1.10 meters where it is caught.


a. Find the velocity of the ball just before it makes contact with the ground.
b. And just after it leaves the ground after the bounce.


Sagot :

a. Between the time the ball is first dropped and the first time it hits the ground, the ball's vertical velocity v at time t is given by

v = -gt

and its height y is

y = 2.00 m - 1/2 gt²

Solve the second equation for time t when the height is y = 0 (corresponding to the moment the ball first hits the ground) :

0 = 2.00 m - 1/2 gt²

1/2 gt² = 2.00 m

gt² = 4.00 m

t² ≈ 0.408163 s²

t ≈ 0.638877 s ≈ 0.639 s

Solve for v in the first equation at time this t :

v = -gt

v ≈ -6.26099 m/s ≈ -6.26 m/s

(That is, the ball hits the ground with a downward velocity of 6.26 m/s.)

b. The ball loses some energy after hitting the ground, and when it bounces back up, so it does so with a smaller upward initial velocity v' ("v prime").

At its maximum height h, the ball has zero vertical velocity. It's in freefall, so acceleration is constant. Then

0² - (v')² = -2gh

Solve for v' using the fact that h = 1.10 m after the first bounce:

(v')² = 2g (1.10 m)

(v')² = 21.56 m²/s²

v' ≈ 4.64327 m/s ≈ 4.64 m/s

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.