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Sagot :
Answer:
M(3/2, -1)
Step-by-step explanation:
[tex](\frac{x_1+y_1}{2},\frac{x_2+y_2}{2})\\ \\(\frac{-8+11}{2},\frac{-7+5}{2})\\\\(\frac{3}{2},\frac{-2}{2})\\\\(\frac{3}{2},-1)[/tex]
Therefore, the midpoint between P(-8, -7) and K(11,5) is M(3/2, -1)
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