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Find the 2nd term in the expansion of (x+4y)^6

in simplest form.


Sagot :

[tex]\textit{binomial expanded }2^{nd}\textit{ term for}\qquad (x+4y)^6\qquad \begin{cases} \stackrel{\textit{2nd term}}{k=1}\\ n=6 \end{cases} \\\\ \stackrel{\stackrel{coefficient}{\downarrow }}{\left(\cfrac{6!}{1!(6-1)!}\right)} \qquad \stackrel{\stackrel{\textit{first term factor}}{\downarrow }}{\left( x \right)^{6-1}} \qquad \stackrel{\stackrel{\textit{second term factor}}{\downarrow }}{\left( 4y\right)^1}\qquad \implies 6(x)^5(4y)^1\implies 24x^5y[/tex]