cadeknolan40
Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Graph the equation y=-x^2-2x+3 on the accompanying set of axes. You must plot 5 points including the roots and the vertex.

Sagot :

Answer:

See below (along with attached graph)

5th point can be of personal choice

Step-by-step explanation:

X-intercepts/Roots

[tex]y=-x^2-2x+3\\\\0=-x^2-2x+3\\\\0=-(x^2+2x-3)\\\\0=-(x+3)(x-1)\\\\x=-3,\: x=1\\\\(-3,0)\:and\:(1,0)[/tex]

Y-intercept

[tex]y=-x^2-2x+3\\\\y=-(0)^2-2(0)+3\\\\y=3\\\\(0,3)[/tex]

Vertex

[tex]x=-\frac{b}{2a}\\ \\x=-\frac{(-2)}{2(-1)}\\ \\x=\frac{2}{-2}\\ \\x=-1\\\\y=-x^2-2x+3\\\\y=-(-1)^2-2(-1)+3\\\\y=-1+2+3\\\\y=4\\\\(-1,4)[/tex]

View image goddessboi
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.