cadeknolan40
Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Graph the equation y=-x^2-2x+3 on the accompanying set of axes. You must plot 5 points including the roots and the vertex.

Sagot :

Answer:

See below (along with attached graph)

5th point can be of personal choice

Step-by-step explanation:

X-intercepts/Roots

[tex]y=-x^2-2x+3\\\\0=-x^2-2x+3\\\\0=-(x^2+2x-3)\\\\0=-(x+3)(x-1)\\\\x=-3,\: x=1\\\\(-3,0)\:and\:(1,0)[/tex]

Y-intercept

[tex]y=-x^2-2x+3\\\\y=-(0)^2-2(0)+3\\\\y=3\\\\(0,3)[/tex]

Vertex

[tex]x=-\frac{b}{2a}\\ \\x=-\frac{(-2)}{2(-1)}\\ \\x=\frac{2}{-2}\\ \\x=-1\\\\y=-x^2-2x+3\\\\y=-(-1)^2-2(-1)+3\\\\y=-1+2+3\\\\y=4\\\\(-1,4)[/tex]

View image goddessboi
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.