Answered

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Brandon has a jar of quarters and dimes with a total value of $10.05. The number of quarters is 3
less than twice the number of dimes. How many quarters and how many dimes does Brandon
have?

Sagot :

rspill6

Answer:

Brandon has 18 Dimes and 33 Quarters  [Beware:  The problem does not state that Brandon owns the coins - he just has them.  Check your pockets]

Step-by-step explanation:

Let D and Q stand for the numbers of Dimes(D) and Quarters(Q).  I'll use pennies instead of dollars, so avoid the clutter of decimal points.

We are told that:

Q = 2D - 3  [The number of quarters is 3 less than twice the number of dimes.]

and

25Q + 10D = 1005   [total value of $10.05]

Substitute the value of Q in the first equation in the second, so that we have an equation with just one unknown, D.

25(2D-3) + 10D = 1005

50D - 75 + 10D = 1005

60D = 1080

D = 18

Q = 2D - 3

Q = 2(18) - 3

Q = 33

=============================

Check

25Q + 10D = 1005

25(33) + 10(18) = 1005  ?

825 + 180 = 1005  YES

----

Q = 2D - 3 ?

33 = 2(18) - 3    YES

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