Answered

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Find the number of sides of a regular polygon in which the measure of an interior angle is three times the measure of an exterior angle.

Sagot :

The sum of the interior angles of any polygon is given by (n-2)180°, where n is the number of sides.

Also sum of all the exterior angles of any polygon is 360°

Given (n-2)180° = 3(360°)

=> n-2 = 6

=> n = 8.

Hence the number of sides of a polygon is 8
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