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How many moles of lithium chloride will be formed by the reaction of chloride with 4.28 mol of lithium bromide in the following reaction (below)? *

How Many Moles Of Lithium Chloride Will Be Formed By The Reaction Of Chloride With 428 Mol Of Lithium Bromide In The Following Reaction Below class=

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Answer:

The answer is 4.28 moles

Explanation:

This is super easy okay, you won't forget this!

Basically mole ratios, we're just looking at the coefficients in front of the compounds, multiplying them, and dividing them as we see fit.

In this example, you can see how you need 2 moles of lithium bromide (LiBr) for the reaction, and 2 moles of lithium chloride (LiCl) will be produced.

Basically, the molar ratio is when you divide numbers and see how much of this do I have for that (if that makes sense).

So if you were to divide the 2 moles of LiBr / 2 moles of LiCl = 1. So we know that the mole ratio for LiBr to LiCl is 1:1 or 2:2, either or, it's the same thing.

SO THE BIG IDEA, if we have 4.28 moles of lithium bromide reacting, we should also have 4.28 moles of lithium chloride produced, BECAUSE the mole ratio is 1:1.

I hope this makes sense please tell me if it doesn't, I will try my best to explain a little more.

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