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Sagot :
The resistance of the combination of resistors given is; 1.5 ohms
How to calculate resistance in series and in parallel
Since 3 of the resistors are in series and each of the resistor has a resistance of 2 ohms, then;
Total resistance; R = 2 + 2 + 2
R = 6 ohms
Now, formula for sum of resistance in parallel is;
1/R = 1/R1 + 1/R2 + 1/R3 ....
Since we have four of the resistor combination above in parallel, then;
1/R = 1/6 + 1/6 + 1/6 + 1/6
1/R = 4/6
R = 6/4
R = 1.5 ohms
Read more about resistors in series and in parallel at; https://brainly.com/question/14883923
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