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A combination consists of three resistors in series. Four similar sets are connected in parallel. If the resistance of each resistor is 2 ohm, find the resistance of the combination..

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The resistance of the combination of resistors given is; 1.5 ohms

How to calculate resistance in series and in parallel

Since 3 of the resistors are in series and each of the resistor has a resistance of 2 ohms, then;

Total resistance; R = 2 + 2 + 2

R = 6 ohms

Now, formula for sum of resistance in parallel is;

1/R = 1/R1 + 1/R2 + 1/R3 ....

Since we have four of the resistor combination above in parallel, then;

1/R = 1/6 + 1/6 + 1/6 + 1/6

1/R = 4/6

R = 6/4

R = 1.5 ohms

Read more about resistors in series and in parallel at; https://brainly.com/question/14883923