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Sagot :
- Initial velocity=50m/s=u
- Final velocity=v=0m/s
- Acceleration=8m/s^2=a
- Distance=s=200m
Apply third equation of kinematics
[tex]\\ \tt\hookrightarrow v^2-u^2=2as[/tex]
[tex]\\ \tt\hookrightarrow (50)^2=2(200)(8)[/tex]
[tex]\\ \tt\hookrightarrow 2500=16(200)[/tex]
[tex]\\ \tt\hookrightarrow 200=2500/16[/tex]
[tex]\\ \tt\hookrightarrow 200>156.25[/tex]
Unfortunately the car cannot make it through
Answer:
No. The car could not make through the light.
Explanation:
- initial velocity is 50 m/s
- can acceleration to 8 m/s²
- Needs to cover 200 metres or more.
- Has 3 seconds.
Formula: [tex]s=ut+\frac{1}{2} at^{2}[/tex]
where s is displacement, u is initial velocity, a is acceleration, t is time
Using the formula:
Distance: 50 * 3 + 1/2 * 8 * 3²
: 186 meters
The car could not make it through.
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