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Graph the line that has a slope of 10 and includes the point (0, 0).​

Sagot :

rspill6

Answer:

See attached graph

Step-by-step explanation:

The equation that has a slope of 10 and intersects (0,0) is:

y = 10x

The slope-intercept form of a straight line equation is y=mx+b, where m is the slope and b the y-intercept (the value of y when x = 0).  

In this case:

m = 10

b is 0 since the value of y when x = 0 is 0 (0,0).

See attached graph.

View image rspill6

[tex]\huge\fbox{Hi\:there!}[/tex]

We are given the slope of the line and a point that it passes through, so we can use the Point-Slope formula:

[tex]\rm{y-y1=m(x-x1)[/tex]

Where

y1 is the y-coordinate of the point, m is the slope and x1 is the x-coordinate.

In this case:

y1=0

m=10

x1=0

Plug in the values:

[tex]\bf{y-0=10(x-0)[/tex]

Solve:

[tex]\bf{y-0=10x[/tex]

[tex]\bf{y=10x}[/tex]

Now, how to graph the line?

Let's look at its equation.

First of all, it has a y-intercept of 0, which means the line touches the y-axis at (0,0)

Now, what about the slope? The slope is 10.

Thus

We move "up 10, over 1, up 10, over 1" and so on, until we have a line.

Then all we have to do is take a ruler and connect the points.

Hope it helps!

~Just a determined gal

#HaveAGreatDay

[tex]\bf{-MistySparkles^**^*[/tex]

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