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Sagot :
Answer:
- 3/10 of the total distance
Step-by-step explanation:
Travelled on Saturday:
- 3/10 of the distance
Remaining distance:
- 1 - 3/10 = 7/10 of the distance
Travelled on Sunday:
- 3/7 of the 7/10, which is
- 3/7*7/10 = 3/10
Answer : 3/10
Here it's given that Peter's family travelled 3/10 of the distance on Saturday . So if we assume the total distance to be 1 , then the remaining distance will be ,
[tex]\sf\longrightarrow 1 - \dfrac{3}{10}=\dfrac{10-3}{10}=\boxed{\dfrac{7}{10}}[/tex]
Again it's given that they travelled 3/7 of the remaining distance on Sunday . So , the distance travelled would be ,
[tex]\sf\longrightarrow \dfrac{3}{7}\times \dfrac{7}{10}=\boxed{\sf \dfrac{3}{10}} [/tex]
Therefore Peter's family travelled 3/10 of the total distance on Sunday .
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