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(image) The figure below is an isosceles triangle surmounted by a semi-circle. Find the area of the entire region.
5 5 40°​

Image The Figure Below Is An Isosceles Triangle Surmounted By A Semicircle Find The Area Of The Entire Region5 5 40 class=

Sagot :

Answer:

12.53

Step-by-step explanation:

∠BCA = (180°-40°)/2 = 70°

Laws of Sines: CA/sin 40° = AB/sin 70° = 5/sin 70°

CA = 5/sin 70° * sin 40° = 3.40

area of semicircle CA = (3.1416 * 1.70²) / 2 = 4.54

By Heron's Formula, area of triangle ABC:

1/4 √(a+b+c) (a+b-c) (b+c-a) (c+a-b) = 1/4 * √13.4*3.4*3.4*6.6

                                                          = 7.99

Entire region area = 4.54 + 7.99 = 12.53

View image lynnkc2000
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