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The height H metres of a ball projected upwards t seconds after being projected is given by H=64t - 16t². Find it's initial velocity​

Sagot :

semsee45

Answer:

initial velocity = 64 m/s

Step-by-step explanation:

Differentiate H = 64t - 16t² to find an equation for velocity:

Velocity = [tex]\frac{dH}{dt}[/tex] = 64 - 32t

Initial velocity (u) is when t = 0:

   u = 64 - 32(0)

⇒ u = 64 - 0

⇒ u = 64 m/s

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