ataeirasta
Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

A visitor makes a list of 11 sights he’d like to see. He is determined to visit at least 8 of these. How many possible choices does he have?

Sagot :

Using the combination formula, it is found that he has 232 choices.

The order in which the sights are seen is not important, hence the combination formula is used to solve this question.

What is the combination formula?

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, the choices are 8, 9, 10 or 11 sights from a set of 11, hence:

[tex]T = C_{11,8} + C_{11,9} + C_{11,10} + C_{11,11} = \frac{11!}{3!8!} + \frac{11!}{2!9!} + \frac{11!}{10!1!} + \frac{11!}{0!11!} = 232[/tex]

He has 232 choices.

You can learn more about the combination formula at https://brainly.com/question/25821700

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.