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Sagot :
So, the time that taken for the astronaut to fall to the surface of the moon is 2.5 s.
Introduction
Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the time required can be calculated by the following equation:
[tex] \sf{h = \frac{1}{2} \cdot g \cdot t^2} [/tex]
[tex] \sf{\frac{2 \cdot h}{g} = t^2} [/tex]
[tex] \boxed{\sf{\bold{t = \sqrt{\frac{2 \cdot h}{g}}}}} [/tex]
With the following condition :
- t = interval of the time (s)
- h = height or any other displacement at vertical line (m)
- g = acceleration of the gravity (m/s²)
Problem Solving
We know that :
- h = height = 5.00 m
- g = acceleration of the gravity = 1.6 m/s²
What was asked :
- t = interval of the time = ... s
Step by step :
[tex] \sf{t = \sqrt{\frac{2 \cdot h}{g}}} [/tex]
[tex] \sf{t = \sqrt{\frac{2 \cdot 5}{1.6}}} [/tex]
[tex] \sf{t = \sqrt{6.25}} [/tex]
[tex] \boxed{\sf{t = 2.5 \: s}} [/tex]
Conclusion
So, the time that taken for the astronaut to fall to the surface of the moon is 2.5 s.
See More
- Time that needed for hearing the splash of fallen rock in the well https://brainly.com/question/26485521
- The speed of the object at a certain height (free fall motion) https://brainly.com/question/26377041
- The relationship between acceleration and the change in velocity and time in free fall https://brainly.com/question/26486625
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