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I need help please and thank you
(show work please)​

I Need Help Please And Thank You Show Work Please class=

Sagot :

Answer:

y = 42x

Step-by-step explanation:

since it is linear it is proportional

using y = mx + c where m is the gradient

working out the gradient pick any two coordinates, I'll use (6, 252) and (12, 504)

[tex]gradient \: = \frac{change \: in \: y}{change \: in \: x} [/tex]

[tex] gradient = \frac{504 - 252}{12 - 6} = 42[/tex]

m = 42

input m = 42 in y = mx + c

the equation is now y = 42x + c

use one of the coordinates (6, 252) or (12, 504), I'm using (6, 252)

y = 42x + c where y = 252 and x = 6, solving for c:

252 = (42 × 6) + c

252 = 252 + c

c = 0

so the final equation is y = 42x